team plays 95 games in a season. if they won 17 more than twice as many games they lost. How many wins and losses did they have?
W + L = 95
W - 2L = 17
Solve simultaneoulsly
3L = 78
etc.
a minor league baseball team plays 88 games in a season . if the team won 17 more then twice as many games as they lost , how many wins and losses did the team have
the team won 10 of its 30 games and lost the rest . What was the team's win-loss ratio?
To find the number of wins and losses for the team, we can set up a system of equations based on the given information.
Let's assume the number of games the team lost is L, and the number of games the team won is W.
According to the given information, the team won 17 more than twice the number of games they lost. So, we can write the equation: W = 2L + 17. (Equation 1)
The total number of games played in a season is 95. So, we can write another equation based on the total number of games: W + L = 95. (Equation 2)
Now we can solve this system of equations to determine the number of wins (W) and losses (L).
Substituting equation 1 into equation 2, we get:
(2L + 17) + L = 95
3L + 17 = 95
3L = 95 - 17
3L = 78
L = 78 / 3
L = 26
Now, substitute the value of L back into equation 2 to determine the number of wins (W):
W + 26 = 95
W = 95 - 26
W = 69
Therefore, the team had 69 wins and 26 losses.