How many milliliters of 14.5 M NH3 are needed to prepare 6.5 liters of 0.40 M NH3?
Why did the NH3 bring a measuring cup to the party? Because it wanted to "mL" the fun!
To calculate the amount of 14.5 M NH3 needed to prepare a 0.40 M NH3 solution, you can use the following equation:
M1V1 = M2V2
Where:
M1 = initial molarity of the NH3 solution (14.5 M)
V1 = volume of the NH3 solution needed
M2 = final molarity of the NH3 solution (0.40 M)
V2 = final volume of the NH3 solution (6.5 L)
Rearranging the equation, we have:
V1 = (M2V2) / M1
Plugging in the values:
V1 = (0.40 M * 6.5 L) / 14.5 M
Calculating, we find:
V1 ≈ 0.18 L
So, approximately 0.18 liters (or 180 milliliters) of the 14.5 M NH3 solution are needed to prepare 6.5 liters of 0.40 M NH3 solution.
To determine the volume of 14.5 M NH3 needed to prepare 6.5 liters of 0.40 M NH3, you can use the formula:
(volume of high concentration solution) * (high concentration) = (volume of low concentration solution) * (low concentration)
Let's plug in the values:
(Volume of 14.5 M NH3) * (14.5 M) = (6.5 L) * (0.40 M)
Simplifying the equation:
Volume of 14.5 M NH3 = (6.5 L) * (0.40 M) / (14.5 M)
Volume of 14.5 M NH3 = 0.228 L
To convert this volume to milliliters, you can multiply it by 1000:
Volume of 14.5 M NH3 = 0.228 L * 1000 mL/L
Volume of 14.5 M NH3 = 228 mL
Therefore, you would need 228 milliliters of 14.5 M NH3 to prepare 6.5 liters of 0.40 M NH3.
To find out how many milliliters of 14.5 M NH3 are needed to prepare 6.5 liters of 0.40 M NH3, we can use the formula:
M1V1 = M2V2
M1 represents the initial concentration, V1 represents the initial volume, M2 represents the final concentration, and V2 represents the final volume.
In this case, we have:
M1 = 14.5 M (initial concentration of NH3)
V1 = ? (unknown initial volume)
M2 = 0.40 M (final concentration of NH3)
V2 = 6.5 L (final volume of NH3)
We need to rearrange the formula to solve for V1:
V1 = (M2 x V2)/ M1
Now we can substitute the values into the formula:
V1 = (0.40 M x 6.5 L) / 14.5 M
By solving this equation, we can find the volume (V1) in liters. However, since we want the answer in milliliters, we need to convert the volume from liters to milliliters.
1 liter equals 1000 milliliters, so we multiply the volume (V1) by 1000:
V1 (in milliliters) = V1 (in liters) x 1000
Now you can calculate V1 to find the number of milliliters of 14.5 M NH3 needed to prepare 6.5 liters of 0.40 M NH3.
mols concd soln = mols diluted soln
M x mL = M x mL