evaluate log3 27

let x = log3</sub? 27

then isn't 3x = 27 ??

to what exponent must you raise 3 to
in order to get 27 ?

To evaluate log3 27, you need to understand what logarithms are and how they work.

A logarithm is the inverse function of exponentiation. Let's consider the base 3 logarithm, denoted as log3. This means that log3 x is the power to which 3 must be raised to obtain x.

In this case, we are evaluating log3 27. We need to find the power to which 3 must be raised to obtain 27.

To determine this, we can rewrite 27 as a power of 3. We know that 3^3 = 27, so we can say that log3 27 = 3.

Therefore, the value of log3 27 is 3.

let x = log3 27

then isn't 3x = 27 ??

to what exponent must you raise 3 to
in order to get 27 ?