what is the balanced formulea equation for the change that takes place at the negative electrode when tin(II) bromide is electrolysed
SnBr2 ==> Sn+2 + 2Br^-
The negative electrode will attract the positive ion. I assume you can take it from here.
what is the meaning of a stable octet
You should post questions that are different from the original in a separate post; otherwise, we may not come back to this question so any follow ups would be ignored.
Many elements tend to add or lose electrons so that their outside shell contains eight (8) electrons (in which their outside shell is like the noble gases of Ne, Ar, Kr, Xe, and Rn---The noble gas He has only two electrons in its outside shell because the first shell can hold only two electrons).
To determine the balanced formula equation for the change that takes place at the negative electrode when tin(II) bromide (SnBr2) is electrolyzed, we need to understand the products formed during electrolysis.
The electrolysis of an ionic compound involves the decomposition of the compound into its constituent ions using an electric current. At the negative electrode (also known as the cathode), reduction occurs, which means the ions gain electrons to form a new substance.
Here are the steps to determine the balanced formula equation:
1. Identify the ions present in tin(II) bromide (SnBr2):
Tin(II) ion: Sn2+
Bromide ion: Br-
2. Determine the reduction reaction:
Since tin is being reduced, it undergoes a reaction that involves gaining electrons. The tin(II) ion gains two electrons (2e-) to form tin metal:
Sn2+ + 2e- -> Sn
3. Write down the balanced formula equation:
The balanced formula equation for the reduction half-reaction at the negative electrode is:
Sn2+ + 2e- -> Sn
So, the balanced formula equation for the change that takes place at the negative electrode when tin(II) bromide is electrolyzed is Sn2+ + 2e- -> Sn.