Two strong magnets on opposite sides of a small table are shown. The long-range attractive force between the magnets keeps the lower magnet in place. Suppose the weight of the table is 26.1 N, the weight of each magnet is 8.99 N, and the magnetic force on the lower magnet is 2.41 times its weight.
a)Find the magnitude of the force of the upper magnet on the lower magnet.
b)What is the magnitude of the normal force of the table on the upper magnet?
c)What is the magnitude of the normal force of the table on the lower magnet?
d)What is the normal force of the ground on the table?
a) Apply Newton's third law
b) Draw a free body diagram for the upper magnet and perform a vertical force balance
c) Do the same for the lower magnet
d) Ground force on table equals total table force on the ground. Consuder all the weights invloved.
Show your work if further assistance is needed.
for d)
do u have to include the normal forces and the magnetic forces of the magnets in the calculation as well?
if so, is the normal force of the lower magnet pointing up or down?
For d: No. They cancel out as internal forces.
ok...thanx :)
could you show the steps for this, if possible?
To find the answers to the given questions, we need to apply Newton's laws and use the given information about the weight of the table, weight of each magnet, and the magnetic force on the lower magnet.
a) The force of the upper magnet on the lower magnet can be determined by multiplying the weight of the lower magnet by the given factor of 2.41. So, the magnitude of the force of the upper magnet on the lower magnet is:
Force of the upper magnet = 2.41 * weight of the lower magnet
Force of the upper magnet = 2.41 * 8.99 N
b) The normal force of the table on the upper magnet can be found by applying Newton's second law, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration. In this case, we are considering the force exerted by the table as the net force on the upper magnet. Since the magnet is stationary and in equilibrium, the net force on it must be zero. Therefore, the normal force of the table on the upper magnet is equal to the weight of the upper magnet (as they cancel each other out).
Magnitude of the normal force of the table on the upper magnet = weight of the upper magnet
Magnitude of the normal force of the table on the upper magnet = 8.99 N
c) Similar to the previous question, the normal force of the table on the lower magnet can be found as the weight of the lower magnet.
Magnitude of the normal force of the table on the lower magnet = weight of the lower magnet
Magnitude of the normal force of the table on the lower magnet = 8.99 N
d) To find the normal force of the ground on the table, we need to consider the equilibrium of forces acting on the table. Since the weight of the table is 26.1 N and the weight of each magnet is 8.99 N, the total weight exerted downward is:
Total weight = weight of the table + weight of each magnet + weight of each magnet
Total weight = 26.1 N + 8.99 N + 8.99 N
The magnitude of the normal force exerted by the ground on the table is equal to the total weight acting downward.
Magnitude of the normal force of the ground on the table = Total weight
Now, you can calculate each of the values using the given information and the equations provided.