a single die isrolled, find the probabilities of:
a) P( an odd number greater than 1)
b) P(number less than 5)
c) P(the number 3 or 7)
I will be happy to crtique your thinking. You wouldn't want someone to just give you the answers.
well since a die has only 6 numbers you would take all the odd numbers out of the six Odd(1,3,5)
so than a probability of an odd # greater than 1 would be P(3,5)
b)number less than five
P(4,3,2,1)
c)i am not sure on this one, but since a die doesnt have a 7 so i have so say.
P(3)
hope it make sense.
To solve these probability questions related to rolling a single die, we need to consider two factors: the total number of possible outcomes (sample space) and the desired outcomes.
In the case of rolling a single die, the sample space consists of six possible outcomes: {1, 2, 3, 4, 5, 6}.
a) P(an odd number greater than 1)
To find the probability of rolling an odd number greater than 1, we need to consider the outcomes {3, 5}. There are two desired outcomes out of the six in the sample space.
Therefore, P(an odd number greater than 1) = 2/6 = 1/3.
b) P(number less than 5)
To find the probability of rolling a number less than 5, we need to consider the outcomes {1, 2, 3, 4}. There are four desired outcomes out of the six in the sample space.
Therefore, P(number less than 5) = 4/6 = 2/3.
c) P(the number 3 or 7)
When rolling a standard six-sided die, there is no possible outcome of 7. So, we can only consider the outcome of 3.
There is one desired outcome (the number 3) out of the six in the sample space.
Therefore, P(the number 3 or 7) = 1/6.
Note: It's important to mention that the probability of an event happening is always between 0 and 1, where 0 means it will not happen, and 1 means it will happen with certainty. The probability is calculated by dividing the number of desired outcomes by the number of total outcomes in the sample space.