physics

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A spelunker drops a stone from rest into a hole. The speed of sound is 343m/s in air, and the sound of the stone striking the bottom is heard 1.46s after the stone is dropped. How deep is the hole? What is it in meters

  • physics -

    time=time down + time up
    time=sqrt(2h/g)+ h/vsound

    solve for time Use the quadratic equation.

  • physics -

    Solve the equation
    t1 + t2 =
    (stone's time required to fall) + (time to hear the splash) = 1.46 s

    (1/2) g t1^2 = H
    t1 = sqrt (2H/g)
    a H = t2 (a is the sound speed, 343 m/s)
    t2 = H/a

    You will have to set it up as a quadratic equation in H, the depth of the well.

  • physics -

    10.24

  • physics -

    a stone is dropped into a well . The sound of the splash is heard 30s after the stone is dropped . What is the depth of the well? Note that the speed of sound in air is 343m / s.

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