GK..please check...Chemistry Help Please

posted by .

Moles of S203^2- = (molarity)(volume):
=(0.032400 mol/L)(0.053 litres S203^2-)
= 0.03240 moles S203^2-

Moles if I2 based on Equation #2:
Moles I2 = (1/2)( 0.03240 moles S203^2-)
= .00086 moles I2

Moles of ClO^- based on Equation #1:
Moles ClO-(aq) = (2/3)(.00086 moles I2)
= .00057 moles ClO^3-

moles of ClO-(aq) = moles of NaOCl
.00057 moles ClO^3- = .00057 moles NaOCl

NaOCl mass = (molar mass * moles) = (74) (.00057) = 0.04235 g

Do we assume this gives us grams of NaOCl per 0.5 mL of bleach solution, since we didn’t divide or multiply 0.0005 L with anything? And to make it NaOCl / 100 mLs of bleach do we multiply the by 100?

  • GK..please check...Chemistry Help Please -

    Okay its not lettin me post up i dunt knwo why but the answer i got was

    NaOCl mass = (molar mass * moles)
    = (74) (.00057) = 0.04235 g

    Do we assume this gives us grams of NaOCl per 0.5 mL of bleach solution, since we didn’t divide or multiply 0.0005 L with anything? And to make it NaOCl / 100 mLs of bleach do we multiply the by 100?

  • GK..please check...Chemistry Help Please -

    Moles of S203^2- = (molarity)(volume):
    =(0.032400 mol/L)(0.053 litres S203^2-)
    = 0.03240 moles S203^2-


    I don't know if you made a typo or not but 0.03240 x 0.0530 is not 0.03240. You need to check your arithmetic. I get something like 0.064 or so for g NaOCl. That is g NaOCl in 0.5 mL (as GK said in his first response to your last posting). So you multiply this (again, just as he said) by 100/0.5 if you want the answer in g/100 mL. By the way, the molar mass of NaOCl is 74.44 and not 74.0. One reason you may be having trouble posting is you can not copy and paste. Try typing it in and you should have no trouble.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    3Cu+8HNO3--> 3Cu(NO3)2+ 2NO+4H2O How many moles of HNO3 are required to react with 6 moles of Cu?
  2. GK..please check...Chemistry Help Please

    Sorry not leting me post entire thing on last post..can you please check Thank- YOu # Chemistry Help Please - GK, Wednesday, October 22, 2008 at 11:24am Reaction #1 (properly balanced): 2ClO-(aq) + 4H+(aq) + 6I-(aq) –> 3I2 + 2Cl-(aq) …
  3. GK or Dr.Bob222...Chemistry please help...

    Please refer to the previous post Chemistry Help Please. Moles of S203^2- = (molarity)(volume): =(0.032400 mol/L)(0.053 litres S203^2-) = 0.03240 moles S203^2- Posted by DrBob222 on Wednesday, October 22, 2008 at 9:37pm in response …
  4. Chemistry: please double check...

    Please double check one last time have to hand it in tomorrow.Thank-You in Advance. This was the lab experiment: ------------------------------------------- A. Standardization of the Sodium Thiosulfate Solution Make up a standard solution …
  5. Chemistry

    I can not determine the answer for this problem...can someone please help me?
  6. Chemistry

    Calculate the average disappearance of A between t=0 min and t=10 min in units of M/s. 0 min there are .065 moles of A 10 min there are .051 moles of A 20 min there are .042 moles of A 30 min there are .036 moles of A 40 min there …
  7. chemistry

    Initially, there are 33 moles of A and 0 moles of B. How many moles of A and B will be present after the system reaches equilibrium?
  8. CHEM MOLES !@@!

    Mole Calculation Worksheet 1) How many moles are in 15 grams of lithium?
  9. physics

    Find the number of moles in 2.00 L of gas at 35.0°C and under 7.41×107 N/m2 of pressure. Select one: a. 0.051 moles b. 51 ×105 moles c. 58 moles d. 5.8 moles
  10. Chemistry

    The combustion reaction of propane is described by the reaction. C3H8 + 5O2 → 4H2O + 3CO2. How many moles of O2 are required to generate 3 moles of CO2?

More Similar Questions