Math
posted by Natalie .
Jill and Matt run on a 400meterlong oval track. They each run 10 laps daily and both run in the same lane. One day, they begin at the same point, but ran in opposite directions. Jill ran at a constant speed that was 2 meters per second faster than Matt's constant speed. Jill passed Matt for the first time in 40 seconds. Jill ran at a constant rate of how many meters per second?
Thanks in advance.

Jill distance = x
Matt distance = (400x)
Jill speed = j
Matt speed = (j2)
distance = rate * time
x = j (40)
(400x) = (j2)(40)
so
(400 40 j) = 40 j  80
I guess you can do it from there.
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