physics

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How many secons apart should two balls be released so that a ball being deopped from a height of H reaches the ground at the same time as a ball dropped from a height of 5H?

  • physics -

    I do not believe the question can be answered with a specific value. Here are my reasons:
    H = gt^2/2
    t = sqrt[2H/g]
    Let the time for 5H = t'
    5H = gt'^2/2
    t' = sqrt[10H/g] = sqrt(5)*sqrt[2H/g]
    The ratio of the two times is:
    t'/t = sqrt(5)*sqrt[2H/g] / sqrt[2H/g] = sqrt(5)
    or
    t' = t*sqrt(5)
    The 2nd ball must be released ( t' - t ) seconds later. The actual number of seconds depends on the value of H:
    ( t' - t ) = sqrt(5)*sqrt[2H/g] - sqrt[2H/g]
    or
    ( t' - t ) = sqrt[2H/g]*[sqrt(5)-1]

  • physics -

    Could you simplify your answer into simple words

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