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4{C3H5(NO3)2}(l)--->6N2(g)+O2(g)+12CO2(g)+10H2O(g)

If a dynamite of 100mL needs 3.5atm to explode, what minimum mass of
C3H5(NO3)2 do I need to put in at 25 degree celcius?

I tried to do this by finding the number of moles by the formula PV=nRT and then convert that into masss.is this correct?

Actually, it makes no sense. I wouldn't begin to try to understand it. If one is talking about the volume and pressure of the products after reaction, 25C is nonsense, as this reaction is very exothermic. I am not certain what was in the mind of the problem author, if anything at all.

my chemistry teacher just made it up. i think she wants to know how much to put in so it will explode.is there anyway to solve it even though it sounds akward?

No.

Agreed, not a solvable problem really. Is this gaseous or liquid volume?

Also is it me or do the N atoms not balance?

Isn't it C3H5(NO3)3 ??

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