A rectangular fence has a perimeter of 1080 feet. The length is 3 feet more than twice the width. I need to know the dimensions and how to figure it out.

width: w

length: 2w+3

so 2w + 2(2w+3) = 1080

solve

I am sure you can take it from here.

how do you do two step equations

don't know what you mean by 'two step' equations but here is how I would continue

2w + 2(2w+3) = 1080
2w + 4w + 6 = 1080
6w = 1080 - 6
6w = 1074
w = 179

then length = 2w + 3 = 2(179) + 3 = 361

To find the dimensions of the rectangular fence, we can set up a system of equations based on the given information.

Let's assume the width of the fence is "x" feet. According to the problem, the length is 3 feet more than twice the width. So, the length can be represented as "2x + 3" feet.

The formula for the perimeter of a rectangle is given by P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.

Substituting the given values, we have:
1080 = 2(2x + 3) + 2x

Simplifying the equation, we get:
1080 = 4x + 6 + 2x

Combining like terms, we have:
1080 = 6x + 6

Now, we can isolate the variable:
1080 - 6 = 6x
1074 = 6x

Dividing both sides by 6:
x = 1074 / 6
x = 179

So, the width of the rectangular fence is 179 feet. Now we can find the length by substituting the value of the width into the given formula:
Length = 2x + 3
Length = 2(179) + 3
Length = 358 + 3
Length = 361

Therefore, the dimensions of the rectangular fence are 179 feet by 361 feet.