algebra
posted by danielle .
What is the solution of the system?
Solve the system of equations using the substitution method.
xy=1
5x+4y=23

Eqn (1) to be mly by 4,
then we have 4x4y=4,
(2)5x+4y=23

9x+ 0=27
9x=27
x=27/9=3
x=3.
to get y,
we substitute in the eqn(1)
(xy=1) as 3y=1
3+1=y
y=2.
Therefore, we get x=3
y=2