A transfer of heat occurs with a pot of 8.0 kg of water that changes from 400 degrees kelvin to 320 degrees kelvin. How much heat is absorbed or given off?

heat=masswater*specificheatwater(320-400)

To calculate the amount of heat absorbed or given off, you need to use the specific heat capacity formula:

Q = m * c * ΔT

where:
Q represents the amount of heat transferred
m is the mass of the substance (in this case, water) in kilograms
c is the specific heat capacity of water, which is 4186 J/kg·K
ΔT is the change in temperature in Kelvin

First, let's convert the change in temperature from Kelvin to Celsius:
ΔT = 320 K - 400 K = -80 K

Now we can substitute the values into the formula:
Q = 8.0 kg * 4186 J/kg·K * -80 K

Calculating the value, we get:
Q ≈ -2,131,840 J

The negative sign indicates that heat is given off by the water, as the temperature is decreasing. Therefore, approximately 2,131,840 Joules of heat is given off by the water during this process.