please help me with my math.

Use the distance formula to find the distance between the following points. Show all your work. Round to the hundredths place.

(4,5) and (7,3)

(2.4,8) and 1,6.3)

(29,4.1) and (53.2, 100)

Here is some tutoring.

http://www.purplemath.com/modules/distform.htm

Now, I will do second one.

Let the first point be point1, and the second point2. It doesn't really matter which is which.

distance=sqrt ( (x2-x1)^2 + (y2-y1)^2 )
= sqrt ( (1-2.4)^2 + (6.3-8)^2 )
= sqrt ( (-1.4)^2 + (-1.7)^2)
= sqrt ( 1.96 +2.89)
= sqrt (4.85)
=2.20

To find the distance between two points using the distance formula, you can follow these steps:

Step 1: Identify the given points.
Let's label the first point as (x1, y1) and the second point as (x2, y2).

Step 2: Recall the distance formula.
The distance formula is √((x2 - x1)^2 + (y2 - y1)^2).

Step 3: Substitute the values into the formula.
For the first pair of points, (4, 5) and (7, 3), we have:
x1 = 4, y1 = 5
x2 = 7, y2 = 3

Plugging these values into the distance formula, we get:
√((7 - 4)^2 + (3 - 5)^2)
= √(3^2 + (-2)^2)
= √(9 + 4)
= √13

So, the distance between (4, 5) and (7, 3) is √13 or approximately 3.61 rounded to the hundredths place.

Now, I'll guide you through the remaining examples:

For the second pair of points, (2.4, 8) and (1, 6.3), we have:
x1 = 2.4, y1 = 8
x2 = 1, y2 = 6.3

Applying the distance formula:
√((1 - 2.4)^2 + (6.3 - 8)^2)
= √((-1.4)^2 + (-1.7)^2)
= √(1.96 + 2.89)
= √4.85

So, the distance between (2.4, 8) and (1, 6.3) is √4.85 or approximately 2.20 rounded to the hundredths place.

For the third pair of points, (29, 4.1) and (53.2, 100), we have:
x1 = 29, y1 = 4.1
x2 = 53.2, y2 = 100

Using the distance formula:
√((53.2 - 29)^2 + (100 - 4.1)^2)
= √(24.2^2 + 95.9^2)
= √(585.64 + 9191.81)
= √9777.45

So, the distance between (29, 4.1) and (53.2, 100) is √9777.45 or approximately 98.87 rounded to the hundredths place.

Remember to always square the differences and sum them up before taking the square root when using the distance formula.