Calcium oxide (quicklime) reacts with water to produce calcium hydroxide (slaked lime).

CaO(s) + H2O(l) Ca(OH)2(s) ÄH = -65.2 kJ

The heat released by this reaction is sufficient to ignite paper. How much heat is released when 29.0 g of calcium oxide reacts?

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-261.15

.285.83
-310.12

To calculate the amount of heat released when 29.0 g of calcium oxide reacts, we need to use the given enthalpy change per mole of reaction.

First, calculate the number of moles of calcium oxide (CaO) using its molar mass. The molar mass of CaO is 56.08 g/mol.

Number of moles = Mass / Molar mass
Number of moles = 29.0 g / 56.08 g/mol

Next, using the stoichiometry of the balanced equation, we can determine the molar ratio of CaO to the enthalpy change.

From the balanced equation: 1 mole of CaO reacts to release 65.2 kJ of heat.

Finally, multiply the number of moles of CaO by the enthalpy change to calculate the heat released.

Heat released = Number of moles x Enthalpy change
Heat released = moles x -65.2 kJ/mol

Let's plug in the numbers:

Number of moles = 29.0 g / 56.08 g/mol ≈ 0.517 mol
Heat released = 0.517 mol x -65.2 kJ/mol ≈ -33.68 kJ

Therefore, when 29.0 g of calcium oxide reacts, approximately -33.68 kJ of heat is released. The negative sign indicates that the reaction is exothermic, meaning it releases heat.