A flight attendant pulls her 69.1 N flight bag a distance of 280 m along a level airport floor at a constant velocity. The force she exerts is
32.7 N at an angle of 50.2◦ above the horizontal.
Find the work done by the force of friction on the flight bag. Answer in units of J.
Find the coe�cient of kinetic friction between the flight bag and the floor.
The horizontal component of her force is equal to the force of friction (constant velocity).
workfriction=frictionforce*distance.
Now for the mu, you have to determine the vertical force, which is mg + vertical component of her pulling force.
To find the work done by the force of friction on the flight bag, we need to calculate the dot product of the force of friction and the displacement of the flight bag.
The formula for work done by a constant force is given by:
Work = Force ⋅ Displacement ⋅ cos(θ)
Where Force is the magnitude of the force of friction, Displacement is the magnitude of the displacement of the flight bag, and θ is the angle between the force of friction and the displacement.
In this case, the Force = 32.7 N and the Displacement = 280 m. The angle θ is not explicitly given, but since the force is at an angle of 50.2° above the horizontal, we can assume that θ is the same angle.
Plugging in the values into the formula:
Work = 32.7 N ⋅ 280 m ⋅ cos(50.2°)
Using a calculator, we can evaluate the cosine of 50.2° and the result of the equation to find the work done by the force of friction.