72% of employees bring their children to day-care centers before work. If there are 465 employees, how many do not bring their children to day-care before work ?
72:465 & x:465 is what I started with but I can not get the correct answer.
need help.
Please recheck your numbers.
72% of 465 = 334.8
Since I've never seen 8/10 of a child -- I suspect that you've made a mistake in posting this question.
I shorten the question, but the word problem is stated exactly as this - the shaded area of the chart represents the number of Acme employees who bring their children to day-care centers before work.if there are 465 employees at Acme, how many do not bring their children to day-care centers before coming to work.
The shaded area is 72%
need help
To find the number of employees who do not bring their children to day-care centers before work, you can set up a proportion:
Let's assume that the number of employees who do not bring their children to day-care centers before work is represented by "x."
The proportion can be set up as:
72/100 = x/465
To solve for "x," you can cross-multiply and then divide:
72 * 465 = 100 * x
33480 = 100 * x
33480/100 = x
x = 334.8
Since we cannot have a fraction of an employee, we need to round down to the nearest whole number, as we are dealing with individual employees.
Therefore, the number of employees who do not bring their children to day-care centers before work is approximately 334.