ok im doing my physics homework and we have to submit the answers online.

i keep getting these questions wrong and i only have one more try can someone please tell me how to work it?

a 2.5 kg otter starts from rest at the top of a muddy incline 94.6 cm long and slides down to the bottom in 0.50s.
What net external force acts on the otter along the incline? in units of N.

a 3.37 kg book is dropped from a height of 2.0m. The acceleration of gravity is 9.81 m/s^2.
what is its acceleration? in units of m/s^2
what is its weight? in units of N

a 2.70 kg block is in equilibrium on an incline of 23.3°
the acceleration of gravity is 9.81 m/s^2/
what is Fn of the incline on the block?
in units of N

A block with a mass of 5.8 kg is held in equilibrium on a frictionless incline of 27.0° by the horizontal force F
the acceleration of gravity is 9.81 m/s^2
what is the magnitude of F? in units of N
what is the magnitude of the normal force. in units of N

i have made diagrams of them to help me out. i was gonna post them here but its not allowed. maybe im doing the diagrams wrong>



Responses

physics - bobpursley, Wednesday, October 15, 2008 at 8:55pm
I would like to see your work.

physics - Claudia, Wednesday, October 15, 2008 at 9:01pm
ok, but how do i put it here if
when i try to post it it says:
You are not allowed to post internet addresses

i have scanned my diagrams and then uploaded them so i can post the html, so you can see my work.
could you tell me how can i post it if it keeps telling me that im not allowed to post internet addresses

Post the web address with spaces, such as this..

w w w . H o t s a u s a g e . D e f ?

F=mgCos(theta)2.27kgx9.8m/s^2Cos23.3

Unfortunately, as a text-based AI, I cannot directly view or analyze diagrams or images. However, I can provide step-by-step guidance on how to solve the problems based on the given information.

1. For the first question about the net external force acting on the otter along the incline:

You can use Newton's second law, F = ma, to find the net external force. In this case, the force causing the otter to slide down the incline is the gravitational force (mg), where m is the mass of the otter and g is the acceleration due to gravity (9.81 m/s^2). The acceleration (a) can be calculated using the kinematic equation: d = 0.5at^2, where d is the distance covered (94.6 cm = 0.946 m) and t is the time taken (0.50 s). Plug in the known values and solve for a. Finally, substitute the calculated acceleration (a) and mass (m) into F = ma to find the net external force.

2. For the second question about the acceleration and weight of the book:

The acceleration of the book can be calculated using the formula a = g, where g is the acceleration due to gravity (9.81 m/s^2). To find the weight of the book, use the formula W = mg, where m is the mass of the book and g is the acceleration due to gravity.

3. For the third question about the normal force of the incline on the block:

The normal force (Fn) is the force exerted by a surface to support the weight of an object resting on it. In this case, the weight of the block (mg) is acting perpendicular to the incline. The component of the weight force parallel to the incline can be calculated by multiplying the weight (mg) by the sine of the angle of the incline (sinθ). Since the block is in equilibrium, the normal force (Fn) must be equal in magnitude and opposite in direction to the weight component parallel to the incline.

4. For the fourth question about the magnitude of force (F) and the normal force:

To find the magnitude of the force (F), you can use the fact that the force (F) is balanced by the component of weight (mg) acting parallel to the incline. The component can be calculated by multiplying the weight (mg) with the sine of the angle of the incline (sinθ). The normal force (Fn) in this case would be equal to the component of weight acting perpendicular to the incline (mg cosθ).

Remember to double-check your calculations and units to ensure accurate answers. If you are still unsure about any step, feel free to ask for further clarification.