posted by Ring

Q. a 2.0 kg block is placed against a spring of force constant 800 N/m, which has been compressed 0.15m. The spring is released, and the block moves 1.2m along a horizontal surface with a coefficient of friction of 0.19. The block then slides up the incline with a coefficient of friction of 0.24. Find the maximum distance the block slides up the incline before sliding back down.

The angle of an incline is 35 degrees

The answer for this question is 0.30m but i don't know how to get this answer.
i need a solution.

1. drwls

Equate the initial compressed spring energy, (1/2) k Xc^2, to the work done against friction PLUS the increase in potential energy, M g H. H is the height the block rises before turning back, and Xc is the spring compression, 0.15 m. The work done against friction is in two parts: the work done on the level surface, M g f1 x1, and the work done on the sloped surface, M g cos 35 f2 x2. The distance the block slides up the ramp is x2 = H/sin 35

Solve your equation for H and then compute H/sin 35

2. Ring

how do i solve for H?

can u explain it more specific and is f friction???

do you mean that (1/2) k Xc^2 is equal to M g H???

thanks

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