Solve:
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)
I do know that (t^2-t-56) can be factored out to (t-8)(t+7)
so I have the equation as (t+24/(t-8)(t+7) +7(t+7)/(t-8)(t+7)-3(x-8)/(t-8)(t+7)
(t-24) + 7(t+7)=3(t-8)
solve for t.
The choices are:
a.)-97/5
b.)122/5
c.)-13
d.)-13/5
Math assistance needed - Shawn, Sunday, October 12, 2008 at 2:56pm
a.)-97/5 is the answer I get is that correct?
I got it thanks
To solve the equation (t+24)/(t^2-t-56)+7/(t-8)=3/(t+7), you correctly factored the denominator t^2-t-56 as (t-8)(t+7).
Now, let's simplify the equation by multiplying every term by (t-8)(t+7) to eliminate the denominators:
(t+24) + 7(t+7) = 3(t-8)
Simplifying further:
t + 24 + 7t + 49 = 3t - 24
Combining like terms:
8t + 73 = 3t - 24
Subtracting 3t from both sides:
5t + 73 = -24
Subtracting 73 from both sides:
5t = -97
Finally, dividing both sides by 5:
t = -97/5
Therefore, the correct answer is option a) -97/5.