the tens digit of a two digit number is 6 more than the units digit. the number is 36 more than the number when the digits are reversed/ what is the number?
This is algebra II?
Let AB be the number.
A-6=B
A*10+B-36=B(10)+A
when i solve for the variables i cancel everything and i don't get an answer
i solved for the longer equation and got a=b+4
i put that in the smaller equation and got b-2=b
iam confused
There is no solution to your question
the only possible cases of a two digit number where the tens digit is 6 more than the units digit are:
60, 71, 82, and 93
the numbers with the digits reversed would be
06, 17, 28, and 39
in each case the difference would be 54, never 36
I'm just really confused about everything
5-(45sin+cos2)-y+344=
alebra like
what is it like in high school
To find the number, let's set up the equations based on the given information:
Let the tens digit be represented by "T" and the units digit be represented by "U".
1. "The tens digit of a two-digit number is 6 more than the units digit" can be expressed as: T = U + 6.
2. "The number is 36 more than the number when the digits are reversed" can be expressed as: 10T + U = 10U + T + 36.
Now, let's solve the equations step by step:
From equation 1: T = U + 6.
Substitute this value of T into equation 2:
10(U + 6) + U = 10U + (U + 6) + 36.
Simplifying equation 2:
10U + 60 + U = 10U + U + 6 + 36.
11U + 60 = 11U + 42.
Simplifying further:
11U - 11U = 42 - 60.
0 = -18.
Since we have arrived at an inconsistent equation, we can conclude that there is no solution for this problem.