my thousand digit is half my ones digit.my houndreds digit is odd and divisable by three.the sum of my hundreds digit,tens digit and ones digit is the same as the sum of my hundreds digit and ones digit. the difference between my houndreds digit and ones digit is equal to my thousand digit. what three numbers could i be?
ABCD is the number
A is 1/2 D
B is 3 or 9
C is zero.
B-D=A
so, B=A+D=1.5D which means that D is 6 or 2
and A is 3 or 1
C is zero
ABCD is 3906 or.....
check my thinking.
or 1302, but the question asks for 3 numbers. What is the third?
To find the three numbers that fit the given conditions, we need to consider the information provided. Let's break it down step by step:
1. The thousand digit is half the ones digit:
- To solve this, let's represent the unknown numbers as follows: ABCD
- Based on the given condition, we have D = 2 * A.
2. The hundreds digit is odd and divisible by three:
- Let's consider the possible values for C:
- C = 1: Not divisible by 3.
- C = 3: Divisible by 3 and odd.
- C = 5: Not divisible by 3.
- C = 7: Not divisible by 3.
- C = 9: Divisible by 3 and odd.
3. The sum of the hundreds, tens, and ones digits is the same as the sum of the hundreds and ones digits:
- This means B + C + D = C + D.
4. The difference between the hundreds and ones digits is equal to the thousand digit:
- This means B - D = A.
Now, let's substitute the values we found and see which combinations satisfy all the conditions:
1. A = 4, B = ?, C = 3, D = 8:
- The number would be 4838.
- The sum of hundreds, tens, and ones: 8 + 3 + 8 = 19.
- The sum of hundreds and ones: 3 + 8 = 11.
- The difference between the hundreds and ones: 8 - 8 = 0.
2. A = 2, B = ?, C = 9, D = 4:
- The number would be 2944.
- The sum of hundreds, tens, and ones: 4 + 9 + 4 = 17.
- The sum of hundreds and ones: 9 + 4 = 13.
- The difference between the hundreds and ones: 4 - 4 = 0.
So, the three possible numbers that fit all the given conditions are 4838 and 2944.