# algebra

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two junked cars were sold at auction to a buyer who paid a total of \$2,000 for both cars. If the more expensive of the two cars was \$240 less than three times the price of the cheaper car, how much was the more expensive car?
how do I solve this word problem?

• algebra -

X + Y = 2000
X = 3Y-240

3Y-240 + Y = 2000
4Y - 240 = 2000
4Y = 2240
Y = 560
X = 1440

• algebra -

the amount of money earned on a job is diretly proportional to the number of hours worked. if \$76 is earned for h of work, how much is earned for 34 h of work.

• algebra -

um. i don't know

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