algebra

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two junked cars were sold at auction to a buyer who paid a total of $2,000 for both cars. If the more expensive of the two cars was $240 less than three times the price of the cheaper car, how much was the more expensive car?
how do I solve this word problem?

  • algebra -

    X + Y = 2000
    X = 3Y-240

    3Y-240 + Y = 2000
    4Y - 240 = 2000
    4Y = 2240
    Y = 560
    X = 1440

  • algebra -

    the amount of money earned on a job is diretly proportional to the number of hours worked. if $76 is earned for h of work, how much is earned for 34 h of work.

  • algebra -

    um. i don't know

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