two junked cars were sold at auction to a buyer who paid a total of $2,000 for both cars. If the more expensive of the two cars was $240 less than three times the price of the cheaper car, how much was the more expensive car?
how do I solve this word problem?
X + Y = 2000
X = 3Y-240
3Y-240 + Y = 2000
4Y - 240 = 2000
4Y = 2240
Y = 560
X = 1440
the amount of money earned on a job is diretly proportional to the number of hours worked. if $76 is earned for h of work, how much is earned for 34 h of work.
um. i don't know
To solve this word problem, we first need to set up an equation based on the given information.
Let's assume the price of the cheaper car is represented by the variable "x." According to the problem, the more expensive car is $240 less than three times the price of the cheaper car. Hence, we can represent the price of the more expensive car as 3x - 240.
The total price paid for both cars is $2,000, so we can write the equation:
x + (3x - 240) = 2000
Now, we can solve this equation to find the value of x, which represents the price of the cheaper car. Once we calculate x, we can substitute it back into the expression 3x - 240 to find the price of the more expensive car.
To solve the equation, we simplify the left side:
4x - 240 = 2000
Next, we isolate the variable:
4x = 2000 + 240
4x = 2240
Finally, we solve for x:
x = 2240 / 4
x = 560
Now, we know the price of the cheaper car is $560. To find the price of the more expensive car, we substitute this value back into the expression:
3x - 240 = 3(560) - 240 = 1680 - 240 = 1440
Thus, the price of the more expensive car is $1,440.