# Math

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x^2-8x+16 would this be the right way
8x^3+16 to start

• Math -

OH NO, you cannot add unlike terms

x^2 - 8x + 16
=(x-4)(x-4)

check it by expanding

BTW, you did not have an "equation".

did you have x^2 - 8x + 16 = 0 ?

then (x-4)(x-4)=0
x = -4

• Math -

I obviously meant x = 4 (not -4)

(that "oldtimers" syndrome hitting again)

• Math -

The factors of x^2 - 8x + 16 are (x-4)(x-4)
You did not write an equation.
If you had written x^2 -8x + 16 = 0, which IS an equation, the answer would be x = 4. That would be the only answer, since both factors are zero when x = 4.

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