hi! ok so im stuck on thes problems. the question is the variable expressions represents the angle measures of a triangle. find the measures of each angle.
ok so the first one is
m<a=(x+30)
m<b=x
m<c=(x=60)
All the angles in a triangle ADD to 180.
so add the above angles, set it equal to 180, and solve for x.
oh ok! boy u have been a real help today!
so then would i set up the problem as
x+30+x+x+60=180
and then would i combine like terms so i get
30+x+60=180
and then
30-60=30
so then 180/30=6
so x=6
Sure! To find the measures of each angle in the triangle, we can start by setting up an equation based on the fact that the sum of the measures of the angles in a triangle is always equal to 180 degrees.
Given:
m<a = (x + 30)
m<b = x
m<c = (x + 60)
To find the value of x, we can equate the sum of these angles to 180 degrees:
(x + 30) + x + (x + 60) = 180
Now let's solve this equation step by step:
1. Combine like terms:
3x + 90 = 180
2. Subtract 90 from both sides of the equation:
3x = 180 - 90
3x = 90
3. Divide both sides by 3 to isolate x:
x = 90 / 3
x = 30
Now that we have the value of x, we can substitute it back into the expressions for m<a, m<b, and m<c to find the measures of each angle:
m<a = (x + 30) = (30 + 30) = 60 degrees
m<b = x = 30 degrees
m<c = (x + 60) = (30 + 60) = 90 degrees
Therefore, the measures of each angle in the triangle are:
m<a = 60 degrees
m<b = 30 degrees
m<c = 90 degrees