A race car constantly accelerates from 0 to 100 m/s,south in 12.5 s.

A)What is the car's acceleration vector?
B) How far does it travel in that time interval?
C) What is its average velocity?

I will be happy to critique your thinking.

I do not know where to start

You should start by listing the given information.

vi = 0
vf = 100 m/s
t = 12.5s

a = (vf-vi)/t

A). a = (100m/s - 0m/s)/12.5 s
a = 8.00 m/s^2

B). You can use several equations for this question. I'm going to use: d = (vf + vi)/2 * t.

d= (100m/s + 0m/s)/2 * 12.5 s
d= 625m

C). Vave = d/t
Vave = (625m/12.5s)
Vave = 50 m/s

I do realize that this answer is 4 years late! :D, but maybe it'll help someone else.

To answer these questions, we need to use the equations of motion. Let's break it down step by step:

A) What is the car's acceleration vector?
Acceleration is the rate of change of velocity with respect to time. In this case, the car's velocity changes from 0 to 100 m/s, south in 12.5 seconds. The acceleration vector can be calculated using the formula:

Acceleration (a) = Change in Velocity (Δv) / Time Interval (Δt)

So, let's calculate the acceleration:
Change in Velocity (Δv) = Final Velocity - Initial Velocity
= 100 m/s - 0 m/s
= 100 m/s

Time Interval (Δt) = 12.5 s

Acceleration (a) = Δv / Δt
= 100 m/s / 12.5 s
= 8 m/s² (south)

Therefore, the car's acceleration vector is 8 m/s² south.

B) How far does it travel in that time interval?
To determine the distance traveled by a uniformly accelerating body in a given time interval, we can use the equation:

Distance (d) = (Initial Velocity (v₀) × Time (t)) + (1/2 × Acceleration (a) × Time (t)²)

Given:
Initial Velocity (v₀) = 0 m/s
Time (t) = 12.5 s
Acceleration (a) = 8 m/s² (south)

Let's calculate the distance:
d = (v₀ * t) + (1/2 * a * t²)
= (0 m/s * 12.5 s) + (1/2 * 8 m/s² * (12.5 s)²)
= 0 m + 500 m
= 500 m

Therefore, the car travels 500 meters in the given time interval.

C) What is its average velocity?
Average velocity is the total displacement divided by the total time. In this case, since the car's acceleration is constant, the average velocity is equal to the final velocity. That is:

Average Velocity = Final Velocity
= 100 m/s (south)

Therefore, the car's average velocity is 100 m/s south.