algebra
posted by marisa .
okay so my question is 8x/3=10
i now that you would substract 8 from both sides but what do you do then

algebra 
bobpursley
multiply each side by 3
Respond to this Question
Similar Questions

math
can anyone help me with these 3 problems I am trying to check my daughters hoime work it has bee na few years. 1. The sum of n and twenty two, multiplied by three, is 78 2. the product of z and 17 is less than or equal to the difference … 
Algebra
2x + 1/2 = x/2 + 1/3 Subtract the x/2 from both sides to get 2x + 1/2  x/2 = + 1/3 Now subtract 1/2 from both sides to get 2x +  x/2 = 1/3  1/2 Then combine terms on both sides and solve for x. Subtract the x/2 from both sides to … 
algebra
8(3/8)k=4 Now try to learn the basic steps of algebra. Subtract 8 from both sides. Why can we do this? 
algerbra
33r=4 Do you wish to solve for r? Put r on one side and everything else on the other. First substract 3 from both sides. 333r = 4  3 combine. 3r = 1 Multiply by 1 3r = 1 Divide both sides by 3 3r/3 = 1/3 r = 1/3 
Help Please
Help to solve this 1/2 (3g2) = g/6 nevermind I was missing a bracket in the solution. multiply both sides by 2 This gives 3g2=g/3 now cross multiply to get 9g6=g now add a g to both sides and +6 to both sides. g=3/4 
Algebra
Can you explain to me how to solve this equation? 
prealgebra
x+5/4=3/4x The next step would be obtained by subtracting 3/4 x + 5/4 from both sides. That gives yoju x/4 = 5/4 Now multiply both sides of the equation by 4. 
algebra/inequalities
Damon, Thanks for the help. Let me see if I get it now. So, 2x < 4 divide both sides by 2 answer is x > 2 I had x < 2, but I reverse the sign since I divided by a 2 on both sides, correct? 
algebra/inequalities
Damon, Thanks for the help. Let me see if I get it now. So, 2x < 4 divide both sides by 2 answer is x > 2 I had x < 2, but I reverse the sign since I divided by a 2 on both sides, correct? 
Algebra
Which of the following describes a correct method for solving the equation below?