logarithms
solve for x
5^(x-1) = 9
take the log base 5 of each side
x-1=log5 9=log10 9 /( log10 5)
http://www.sosmath.com/algebra/logs/log4/log43/log43.html
?
can i do
x-1= log9/log6
x=(log9/log5) + 1 ?
To solve for x in the equation 5^(x-1) = 9, we can use logarithms.
Step 1: Take the logarithm of both sides of the equation. We can use any base for the logarithm, but let's use the common logarithm (base 10) for this example.
log(5^(x-1)) = log(9)
Step 2: Use the logarithmic property to bring down the exponent.
(x-1) * log(5) = log(9)
Step 3: Divide both sides of the equation by log(5) to isolate x.
x - 1 = log(9) / log(5)
Step 4: Add 1 to both sides of the equation to solve for x.
x = 1 + (log(9) / log(5))
Using a scientific calculator, you can find the values of log(9) and log(5), and then substitute them into the equation to calculate x.