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the price p and the quantity x sold of a certain product obey the demand equation

p=(-1/3)x + 100

o is < or equal to x < or equal to 300

A) express revenue R as a function of x

b) what quantity x maximizes revenue.

  • math -

    you finish..

    Take the deriviative of R with respect to x, set to zero, solve for x.

  • math -

    so would the revenue be

    (-1/3)x + 100 * 300

    I don't understand- how would you multiply by x is its inequalities?

    Also, what is the deriviative?

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