A 265 g aluminum engine part at an initial temperature of 2.00°C absorbs 84.5 kJ of heat. What is the final temperature of the part (c of Al = 0.900 J/g·K)?
Heat=massAl*specificheat*(tf-ti)
solve for tf. Watch units.
To find the final temperature of the aluminum engine part, we can use the equation:
q = mcΔT
where q is the heat absorbed by the object, m is the mass of the object, c is the specific heat capacity of the material, and ΔT is the change in temperature.
In this case, we are given:
- The mass of the aluminum engine part, which is 265 g,
- The initial temperature of the part, which is 2.00°C,
- The heat absorbed by the part, which is 84.5 kJ,
- And the specific heat capacity of aluminum, which is 0.900 J/g·K.
First, we need to convert the heat absorbed from kilojoules to joules:
84.5 kJ * 1000 = 84,500 J
Now, we can rearrange the equation to solve for the change in temperature:
ΔT = q / mc
Substituting the given values:
ΔT = 84,500 J / (265 g * (0.900 J/g·K))
Calculating the value inside the parentheses:
(265 g * 0.900 J/g·K) = 238.5 J/K
Finally, we can solve for ΔT:
ΔT = 84,500 J / 238.5 J/K
ΔT ≈ 354.55 K
The change in temperature is 354.55 K.
To find the final temperature, we add the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 2.00°C + 354.55 K
Converting the Celsius temperature to Kelvin:
Final temperature = 2.00 + 354.55
Final temperature ≈ 356.55°C
Therefore, the final temperature of the aluminum engine part is approximately 356.55°C.