# math 116

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1) you are planning to spend no less than \$6,000 and no more than \$10,000 on your landscaping project.
Q1: write an inequality that demonstrates how much money you will be willing to spend on the project.
A1: 6,000 greater than > and equal = to 10,000

Q2: suppose you want to cover the backyard with decorative rock and plant some trees as the first phase of the project. you need 30 tons of rock to cover the area. if each ton cost \$60 and each tree is \$84, what is the maximum number of trees you can buy with a budget for rock and trees of \$2,500? write an inequality that illustrates the problem and solve. express your answer as an inequality and explain how you arrived at your answer.

A2: 30(60) + 84x = 2500
1800 + 84x = 2500
subtract both sides by 1800 to get:
-1800 + 84x = 2500-1800
84x = 700
divide both sides by 84 to get:
x = 8.33

• math 116 -

The first answer I don't understand at all.

I would do this...

6000<amountIspend<=10000

• math 116 -

In this particular class the answer I believe to be true is in an equation form, not with words.

\$6,000 <(underline this)\$10,000

and that's it.

• math 116 -

P <= \$10,000 + => \$6,000

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