Math
posted by Anonymous .
The weekly salaries of 100 recent graduates of a private women's college are normally distributed with a mean of $600 and a standard deviation of $80. Determine the interval about the sample mean that has a 1% level of confidence. Use t=2.58
I don't know.
600/sqrt100
60
80+2.58*60
2334.8 and 74.8

Its 600 +_ 2.58*80