A small city produces 500,000 cubic ft. of garbage per week. If all of this garbage were stacked neatly (in a nice vertical pile) on a 100-yard by 60-yard football field, how high would the pile be (in feet)?
First, let's figure the area of the football field in square feet.
300 * 180 = 54,000 square feet
Since the volume of a cube = length * width * height, we need to divide 500,000 by 54,000 to find the height.
Another way to approach this problem:
300 * 180 * x = 500,000
Thank you! My mind is so fried right now I could not even think!
You're welcome.
To determine the height of the pile of garbage, we need to find out the total volume it occupies.
First, let's convert the dimensions of the football field to feet:
- 100 yards = 300 feet
- 60 yards = 180 feet
To calculate the volume, we multiply the area of the field by the height. However, we need to find the height, so we rearrange the formula to solve for it.
Let's calculate the area of the football field:
Area = Length × Width
Area = 300 ft × 180 ft
Area = 54,000 sq. ft
Since we know the volume of garbage produced per week is 500,000 cubic ft and the area of the field is 54,000 sq. ft, we can calculate the height of the pile using the formula:
Height = Volume / Area
Height = 500,000 cu. ft / 54,000 sq. ft
Therefore, the height of the pile of garbage would be:
Height = 9.26 feet (approximately)
So, if all the garbage is neatly stacked on the football field, the height of the pile would be approximately 9.26 feet.