Use exponents to write the prime factors of 32 and 81, I have no idea???Help
32 = 2*2*2*2*2 = 2^5
81 = 3*3*3*3 = 3^4
Prime factors of 32? 2 to some power. Try 2x2x2x2x2 or 2^5
81 is 9x9, so it must be in prime 3x3x3x3 or 3^4
Sure, I can help you with that!
To find the prime factors of a number, we need to decompose it into its prime factors. Let's start with 32.
Step 1: Divide 32 by the smallest prime number, which is 2. We get 32 ÷ 2 = 16.
Step 2: Now, divide 16 by 2 again. We get 16 ÷ 2 = 8.
Step 3: Continue dividing by 2 until we can't divide anymore. We get:
8 ÷ 2 = 4
4 ÷ 2 = 2
2 ÷ 2 = 1
Step 4: The prime factors of 32 are the divisors we used, in this case, 2. Count how many times we divided by 2 (4 times). So we express it as 2^4.
Therefore, the prime factors of 32 can be written as 2^4.
Now let's do the same for 81.
Step 1: Divide 81 by the smallest prime number, which is 3. We get 81 ÷ 3 = 27.
Step 2: Divide 27 by 3 again. We get 27 ÷ 3 = 9.
Step 3: Continue dividing by 3 until we can't divide anymore. We get:
9 ÷ 3 = 3
3 ÷ 3 = 1
Step 4: The prime factors of 81 are the divisors we used, in this case, 3. Count how many times we divided by 3 (4 times). So we express it as 3^4.
Therefore, the prime factors of 81 can be written as 3^4.
I hope this helps!