Time taken in mins for student to walk to school.
1-5 mins (4 students)
6-10 mins (7 students)
11-15 mins (10 students)
16-20 mins (20 students)
21-25 mins (6 students)
26-30 mins (3 students)
1)Estimate the probability that a student selected at random will take at least 21 mins to walk to school
2)The time to nearest minute taken by each of 2 other students to walk to school in 33 mins and state the interval in which this would lie
1) (6+3)/(4+7+10+20+6+3)
2) What do you mean by "each of the other two students?" Other than what? According to your table, no student takes longer than 30 minutes to walk to school.
To solve these questions, we can first calculate the total number of students and then use that information to find the probability and interval.
1) To estimate the probability that a student selected at random will take at least 21 minutes to walk to school, we need to find the total number of students who take at least 21 minutes and divide it by the total number of students.
In this case, there are 6 students who take 21-25 minutes and 3 students who take 26-30 minutes. So the total number of students who take at least 21 minutes is 6 + 3 = 9.
The total number of students is the sum of all the students in each time interval: 4 + 7 + 10 + 20 + 6 + 3 = 50.
Therefore, the estimated probability that a student selected at random will take at least 21 minutes to walk to school is 9/50 or 0.18 (18%).
2) To determine the interval in which the time taken by each of the two students lies, we need to find the interval that contains the given time of 33 minutes.
Looking at the given intervals, we can see that the time interval of 26-30 minutes includes the value of 33 minutes. Therefore, the two students' time is likely to lie in the interval of 26-30 minutes.