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physics

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A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 18.0 m/s. The cliff is 50.0m above a flat, horizontal beach. With what angle of impact does the stone land (in degrees).

  • physics -

    v = Vo -9.8 t
    z = h + Vo t - 4.9 t^2
    here Vo = initial speed up = 0
    h = 50
    z = final height = 0
    so
    0 = 50 - 4.9 t^2
    so t = 3.19 seconds to fall
    v = 0 - 9.8 * 3.19 = -31.3 m/s
    so the speed down is 31.3 and the horizontal speed is still 18
    tangent of angle from vertical = 18/31.3

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