MATH

posted by .

solve
6x^2 - 5x +1 = 0
is this correct?

6x^2 - 2x - 3x + 1=0
-2x(-3x+1) 1(-3x +1)
(2x-1)=0 (3x-1)=0
x=1/2 x=1/3

  • MATH -

    The final answer is correct but there is an intermediate step that is wrong. You should have written
    (2x-1)(3x-1) = 0
    as the factoring step.

    You did break up the quadratic correctly into
    -2x(3x-1) + (-3x+ 1)
    which can be written
    (-3x+1)(-2x+1) = (3x-1)(2x-1)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math,correction,plz

    can someone correct this forme solve 7/5 = 35/x My answer: x = 25 solve x/2 minus x/3 = 3 My answer: x = 18 Both are correct
  2. math,correction

    Is this correct: Solve: (x+5)^2 = 3 I get: x = -5 (+/-) sqrt (3) Problem #2 Solve: 5(x-2)^2 = 3 I get: x = 3 (+/-) ((sqrt(3))/(5) No on the second. YOu have take the sqrt5 slso, so x= 2+- sqrt(3/5) correct on the first.
  3. Algebra

    1.Solve (x)/(x+10)+(x-3)/(x+2)=7/5..I got that there is no solution, is that correct?
  4. Algebra 2

    1. Solve the following for x. 3-(x+(-4))= 2x-6+5x I figured that the answer is no solution. Is this correct?
  5. Math

    T=10d+20 Solve for d. I got T/10-2=d Is this correct?
  6. math 115

    1. Nina's car payment is $362.57 per month for 4 years. how much will she pay altogether?
  7. Pre-Cal

    1)find f(g(x)) f(x) = x^2 + 2x g(x) = 1/x x^3 + 2x Is this correct?
  8. Math

    Factor the polynomial P(x)=x^3-2x^2-13x-10. Then solve the equation P(x)=0. This is what I got: P(x)=(x+1)(x^2-3x-10) P(x)=(x+1)(x-5)(x+2) When it says solve the equation P(x)=0 does it means solve for x?
  9. Math #2

    If I had a math problem 2x^4 x y^-4 x z^-3 / 3x^2 x y^-3 x z^4. In simpler terms it would look like this: 2x^4 X y^-4 X z^-3 ------------------- 3x^2 X y^-3 X z^4 When I tried to solve this I got 6x^2 X y^-1 X 2^-7. Am I correct?
  10. Math

    108 is 46% of what number? Write and solve a proportion to solve the problem. I think it's 38 correct me if I'm wrong

More Similar Questions