Imagine that you have a 7.00 gas tank and a 3.00 gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 145 , to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time?
Is the answer 62.1 atm
Answered above.
Imagine that you have a 6.00L gas tank and a 4.00L gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 145atm , to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time? Assume ideal behavior for all gases.
87 atm
91.1 atm
To find the answer, you need to consider the volume and pressure of each gas tank.
The first step is to convert the given pressures to the same unit. Both tanks have a pressure of 145 atm.
Since you want to run out of both gases at the same time, it means that they should have the same number of moles. The ideal gas law can help us determine the relationship between pressure, volume, and number of moles.
The ideal gas law equation is: PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Since both tanks have the same volume (7.00 and 3.00), and we want to run out of each gas at the same time, it means that the number of moles should be the same. The temperature is constant as well.
For oxygen tank:
P1 * V1 = n1RT (1)
For acetylene tank:
P2 * V2 = n2RT (2)
We want n1 = n2, and since R and T are the same, the equations become:
P1 * V1 = P2 * V2
Now, you can substitute the given values and the pressure of the oxygen tank (P1 = 145 atm) into the equation:
145 * 7.00 = P2 * 3.00
Now, you can solve for P2:
145 * 7.00 / 3.00 = P2
The answer is approximately P2 ≈ 337.67 atm.
So, the correct answer is not 62.1 atm. Instead, you should fill the acetylene tank to a pressure of approximately 337.67 atm to ensure running out of both gases at the same time.