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I'm not sure of how to solve word problems. The question is,"One lawn fertilizer is 24% nitrogen and another is 12% nitrogen. How much of fertilizer should be mixed to obtain 100 kg of fertilizer that is 21% nitrogen?"

  • math -

    see the other post.

  • math -

    Let m1 and m2 be the masses of fertilizer at 24% and 21% respectively. Then write:

    Eq. 1: m1 + m2 = 100
    Eq : (.24m1 + .21 m2)/(m1 + m2)= .21

    The second equation is called a weighted average. Solving simultaneously yields:

    m1 = 75 kg
    m2 = 25 kg

    Checking:

    (.24×75 + .21× 25)/100 = .18 + .03 = .21
    QED

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