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How would you solve for x in this equation:
(x^2-9)(2x-1)=0

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    For the problem, a value of x which makes a factor 0 is a solution.
    (x^2-9)(2x-1) = 0
    factoring (x^2-9) further
    (x+3)(x-3)(2x-1) = 0
    For each factor, what value of x will make the term 0?
    The first term, (x+3), will be 0 for x=-3.
    The second term is 0 for x=?
    The third term is 0 for x=?

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