Calculus
posted by George .
Find a formula for the derivatives of the function m(x)=1/(x+1)
IS the answer 1/(x+h)(x+h+1)

[(x+1)(0)  1(1)]/(x+1)^2
=1/(x+1)^2
=1/(x^2+2x+1)
now doing it as a limit you must let h go to zero
[f(x+h) f(x)]/h as h >0
[1/(x+h+1)1/(x+1)]/h
[(x+1)(x+h+1)]/[h(x+h+1)(x+1)]
1/(x+h+1)(x+1)
as h >0
1/[(x+1)(x+1)]
1/(x^2+2x+1) as we knew
Respond to this Question
Similar Questions

Calculus
Find a formula for the derivatives of the function m(x)=1/(x+1) Please help.....Any assistance would be greatly appreciated. 
calculus  (derivatives)
Find the derivative of the function f by using the rules of differentiation. F(x) = 3 ã x 
calculus
Find the first and second derivatives of the function. h(x) = sqrt x^2 + 1 
Calculus  First Derivatives
Find K'. Y = K^(0.25) * L^(0.75).... relates to CobbsDouglas function (dL/dK) = 0.25 (K/L)^(0.25) I got to this.... but answer is... (dL/dK) = 0.25 Y/L < Please provide a full solution (all steps..) to get to this.... 
CALCULUS DERIVATIVES CONTINUITY
Let f be the function defined by the piecewise function: f(x) = x^3 for x less than or equal to 0 x for x greater than 0 Which of the following is true? 
Calculus
Find the derivatives of the function k(x)=sqrt(sin(2x))^3 I think I have the answer and was wondering if i had it correct k'(x)=2sin(x)^3+8sin(x) 
Calculus
Find the derivatives of the function f(t)=cosh^2(4t)sinh^2(4t). Simplify your answer completely. 
Derivatives
Find the derivatives of: 1. H(x)= sin2xcos2x The answer given is 2cos4x. My question is, how in the world did they get that!? 
Calculus Help
The formula C =5/9(F − 32), where F ≥ −459.67, expresses the Celsius temperature C as a function of the Fahrenheit temperature F. Find a formula for the inverse function. What is the domain of the inverse function? 
calculus
Find the derivatives of the following function: i)y=3x^3 +2x^2 + x2