What is the molality of a sodium chloride solution if 3.5 grams of the salt is added to 998 g of water
Your Answer:
mols = g/molar mass
molality = mols/kg solvent
To calculate the molality of a solution, we need to know the amount of solute (in moles) and the mass of the solvent (in kilograms).
First, we need to find the moles of sodium chloride (NaCl) in the solution. We can do this by using the molar mass of NaCl, which is 58.44 g/mol.
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
Moles of NaCl = 3.5 g / 58.44 g/mol
Next, we need to convert the mass of the solvent (water) into kilograms.
Mass of water = 998 g = 998 g / 1000 g/kg = 0.998 kg
Now that we have both the moles of NaCl and the mass of the water in kilograms, we can calculate the molality.
Molality (m) = Moles of NaCl / Mass of water in kg
Molality (m) = (3.5 g / 58.44 g/mol) / 0.998 kg
Using a calculator, we can simplify this further to get the molality of the sodium chloride solution.