Math/Calculus
posted by Kate .
Find k so that the following function is continuous on any interval:
f(x)= kx
0 (less than or equal to) x (less than) 2
3x^2
2 (less than or equal to x)
i know the answer is 12 but i don't know how to arrive at that. could you please walk me through the steps? thanks.

kx and 3x^2 are continuous where they apply. What you have to to is make sure they both give the same value at x=2, where one functional form changes to the other.
Thus require that 3x^2 = kx at x = 2.
3*4 = 2k
k = 6. The value of the function at x=2 is 12.
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