# Math

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A collection of 30 coins worth \$5.50 consists of nickels, dimes, and quarters. There are twice as many dimes as nickels. How many quarters are there?

• Math -

Let the number of nickels be N
let the number of dimes be D, so D = 2N
let the number of quarters be Q
but Q would then be 30-N-D
= 30 - N - 2N
= 30 - 3N

now form an equation using the "value" of those coins:
5(N) + 10(2N) + 25(30-3N) = 550

solve for N, then backsubstitute for the others.
Let me know what you got.

• Math -

so i did...
5n+10(2n)+750-75n=550
5n+20n-75n=-200
-50n=-200
n=4

four nickels
eight dimes
12 quarters

.. that's not right! D:

• Math -

4 nickels
8 dimes, and
30-4-8 = 18 quarters, (how did you get 12?)

check: 4(5) + 8(10 + 18(25) = 550

• Math -

ohh!
for some reason i multiplied 4 and three to get 12 quarters..

wow silly mistake!

thanks so much for the help!!

• Math -

fuch et just guess

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