What is the approximate temperature of the solution after 1.75 if it is 19 degree celcius at 1.5 and 24 degree celcius at 2.0 minute?
Can anyone say how to do it exactly?
On the assumption - and it IS an assumption - that the temperature is rising at roughly a constant rate, then it ought to be halfway between 19 and 24 degrees (since 1.75 minutes is halfway between 1.5 and 2 minutes), which would be 21.5 degrees. But the phrasing of your question implies that it's actually part of a larger question, so my assumption might not be correct.
no that's correct. thank you so much... it really worked.
To find the approximate temperature of the solution at 1.75 minutes, we can use linear interpolation. Linear interpolation is a method of estimating an unknown value within a range based on two known values.
Here's how to do it exactly:
1. Calculate the temperature change per minute:
- Subtract the temperature at 1.5 minutes from the temperature at 2.0 minutes: 24°C - 19°C = 5°C
- Divide the temperature change by the time difference: 5°C / (2.0 min - 1.5 min) = 10°C/min
2. Determine the time difference between the desired time (1.75 min) and the known time (1.5 min): 1.75 min - 1.5 min = 0.25 min
3. Multiply the time difference by the temperature change per minute: 0.25 min * 10°C/min = 2.5°C
4. Add the calculated temperature change to the temperature at 1.5 minutes to find the approximate temperature at 1.75 minutes:
- 19°C + 2.5°C = 21.5°C
Therefore, the approximate temperature of the solution at 1.75 minutes is approximately 21.5 degrees Celsius.