physics
posted by Jeff .
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later. What was the rocket's acceleration?

consider the bolt when on the rocket.
Vfbolt=a*4
hfbolt=1/2*a*16=8a
Now in the free fall portion, these become vi, and hi for the bolt
vfbolt=viboltg*6.1=4a6.1g
hfbolt=6.1*4a1/2 g 6.1^2+8a=0
from this second equation
you can solve for a. 
5.627 m/s^2