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A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later. What was the rocket's acceleration?

  • physics -

    consider the bolt when on the rocket.

    Vfbolt=a*4
    hfbolt=1/2*a*16=8a
    Now in the free fall portion, these become vi, and hi for the bolt

    vfbolt=vibolt-g*6.1=4a-6.1g
    hfbolt=6.1*4a-1/2 g 6.1^2+8a=0
    from this second equation
    you can solve for a.

  • physics -

    5.627 m/s^2

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