What si the pH of a solution of 10^-8 M HCl in H2O?
It is a trick question. This HCl is very dilute, the H+ contribution from it is 1/10th the contribution from the water (H+=10^-7).
So here, the H+ is 1.1*10^-7.
pH=-log(1.1*10^-7)=6.96...hardly acid, of course.
A bag contains a mixture of copper and lead BBs. The average density of the BBs is 9.60 .Assuming that the copper and lead are pure, determine the relative amounts of each kind of BB.
Express your answers numerically separated by a comma.
8.3
To determine the pH of a solution, you need to know the concentration of hydrogen ions (H+) in the solution. In this case, you are given that the solution is 10^-8 M HCl, which means the concentration of H+ ions is also 10^-8 M.
pH is defined as the negative logarithm (base 10) of the H+ concentration. Mathematically, it can be expressed as pH = -log[H+].
Using this formula, you can calculate the pH of the solution:
pH = -log(10^-8) = -(-8) = 8
Therefore, the pH of the solution is 8.