hi,
I am trying to find the domain and range,
of this equation, in interval notation.
y = 4/(x+3) , can you please help?
Of course! To find the domain and range of the equation y = 4/(x+3) in interval notation, we need to consider the restrictions on the values of x and the corresponding values of y.
Let's start with the domain. The domain represents all the possible values that x can take in the equation. In this case, the only restriction we have is that the denominator, (x + 3), should not be equal to zero.
So, to find the domain, we need to solve the equation (x + 3) ≠ 0. By solving it, we get:
x + 3 ≠ 0
x ≠ -3
Therefore, the domain for this equation is all real numbers except -3. In interval notation, we represent this as (-∞, -3) U (-3, +∞).
Moving on to the range. The range represents all the possible values that y can take. Since the numerator is a constant value, y = 4, and the denominator, (x + 3), can take any real number except zero, we can say that y can take any real value except 0. In interval notation, we represent this as (-∞, 0) U (0, +∞).
So, the domain in interval notation is (-∞, -3) U (-3, +∞) and the range is (-∞, 0) U (0, +∞).