im trying to explain to my brother how to do graph this problem put im not sure how to solve it either.
(x-3)^2+(y+5)^2=9
so if someone can explain how to graph this it would be greatly appreciated
- IT would be sumthing like that
(x-3)^2 + (y+5)^2 = 9
- opening the brackets by (a + b)^2 { A^2 + 2(a)(b) + b^2 )
- (x^2 - 6x + 9)+(y^2 + 10y + 25)=9
- nOw apply quadratic formula
- Put the value in the above equation and find the value of x and y
To graph the equation (x-3)^2 + (y+5)^2 = 9, you can follow these steps:
Step 1: Identify the Center
The equation is in the standard form for a circle, (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle, and r represents its radius. In this case, (h, k) = (3, -5), so the center of the circle is at point (3, -5).
Step 2: Determine the Radius
The radius of the circle is given by r = √9, which simplifies to r = 3.
Step 3: Plot the Center
On a graph paper, locate the point (3, -5), which represents the center of the circle.
Step 4: Plot Points Using the Radius
From the center point, move 3 units in each direction (up, down, left, and right) to find points on the circle. These points will be the endpoints of the circle's diameter. Mark these points on your graph paper.
Step 5: Sketch the Circle
Using the points from Step 4, sketch a smooth curve connecting them. Make sure the curve passes through all of the points to form a circle.
Step 6: Add Any Additional Information
If there are any specific instructions or restrictions given in the problem, take them into account and add that information to your graph if needed.
By following these steps, you should be able to graph the equation (x-3)^2 + (y+5)^2 = 9 correctly.